Question

A particle is thrown up from a window and moves with constant gravitational acceleration of 10m/s^2 downwards. Its initial velocity is 4 m/s upwards and it finally hits the ground with a velocity 10 m/s. For how long was the particle moving?

Answer 1

Answer: PLEASE MARK AS BRAINLIEST!!!!!! HOPE IT HELPED YOU

1.4s

Explanation:

Given

U=4m/s

velocity=10m/s

a=10m/s^2

v=10m/s

now we need to find time.

(1)  v=u+at

   0=4-10t

  $\frac{-4}{-10}$=t,   t=4/10

   thats time taken to reach back to the window, now we need to find the        time taken to hit the ground.

(2)   since it hits the ground at 10m/s

       v=u+at

         10=0+10t    (Its positive since gravity is acting with the ball causing it to      accelerate)

   10=10t

  t=1

now to find the time taken to hit the ground we add (1)+(2)

= 4/10+1

=0.4 +1

=1.4s

Answer 2

Answer: PLEASE MARK AS BRAINLIEST!!!!!! HOPE IT HELPED YOU

1.4s

Explanation:

Given

U=4m/s

velocity=10m/s

a=10m/s^2

v=10m/s

now we need to find time.

(1)  v=u+at

  0=4-10t

 =t,   t=4/10

  thats time taken to reach back to the window, now we need to find the        time taken to hit the ground.

(2)   since it hits the ground at 10m/s

      v=u+at

        10=0+10t    (Its positive since gravity is acting with the ball causing it to      accelerate)

  10=10t

 t=1

now to find the time taken to hit the ground we add (1)+(2)

= 4/10+1

=0.4 +1

=1.4s