Question

A particle is thrown up vertically with a velocity of 50 metre per second what will be its velocity at the highest point of the journey how I would the particle Christ what time would it take to reach that highest weight take G is equal to 10 metre per second​

Answer 1

Answer:

velocity=0

time = 5 sec

maximum height= 125 m

Explanation:

As the body is thrown vertically upward, the final velocity at the highest point of its journey would be 0.

The time taken to attain this height can be given by,

v=u+at

0=u+at

-u=at

t=(-u)/a

Since the body is moving upward, the value of acceleration will be equal to (   -g)

therefore,

t=-u/-g

minus gets cancelled

t=u/g

here,

u=50 m/s

g=10 m/s²

t=50/10

 =5 sec

Maximum height attained is given by

Hmax=u²/2g

         =(50)²/20

         =2500/20

         =125 m

hope it helped and pls mark as brainliest:)

Answer 2

Answer:

Ur answer will be 125 m and 5 sec