A particle is thrown up vertically with a velocity of 50 m/s. What will be its velocity at the highest point? How high would the particle rise? What time would it take to reach the highest point (g=10m/s2)
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solve this question on this equation of motion vf=vi+gt and then to find distance use third equation of motion 2as=vfsquare-visquare and here vf will be zero
khan45:
sorry bro to find furthur distance here will be vf zero in that case is not zero understand
Oh, I've already managed to solve it on my own. Thank you very much, though!
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