Question

A particle is thrown up vertically with a velocity of 50m/s. What will be its velocity at the highest point of journey? How high would the particle rise? What time would it take to reach the highest point? ( take g= 10ms-2).

Answer 1

u= 50m/s
g= -10m/s^2

The velocity at the highest point will be 0 m/s
Thus v=0

Height can be calculated by

2gs=v^2-u^2
-20s= -2500
s= 125m

Time :
v= u+gt
0=50-10t
-50=-10t
t= 5sec

Answer 2

Velocity = 0, s = 125m, t = 5sec

Explanation:

Given that,

u(initial velocity) = 50m/s

g(accleration due to gravity) = -10m/s^2

∵ v = 0(at the highest point)

While Height can be measured by

$v^{2} - u^{2}$ = 2gs

$o^{2} - 50^{2}$ = 2 * (-10) * s

-2500  = -20s

∵ s= 125m

and Time can be calculated using:

u + g * t = v

50 - 10t  = 0

-10t  = -50

∵ t = 5sec

Learn more: Velocity

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