Question

A particle is thrown up vertically with a velocity of 50m/s.What will be its velocity at the highest point of the journey?How hogh would the particle rise?What time would it take to reach the highest point?Take g = 70m/s2.​

Answer 1

Answer:

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Answer 2

u= 50m/s

g= -10m/s^2

The velocity at the highest point will be 0 m/s

Thus v=0

Height can be calculated by

2gs=v^2-u^2

-20s= -2500

s= 125m

Time :

v= u+gt

0=50-10t

-50=-10t

t= 5sec

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