A particle is thrown up vertically with a velocity of 50m/s . what will be its velocity at the highest point of journey ? How high would the particle rise ? What time would it take to reach the highest point ? ( take g=10m/s² )
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u = 50 m/s
v = 0 m/s
g = -10m/s2
We know that, v = u + gt
t = (v - u) / g = (0 m/s - 50 m/s) / -10m/s2= -50m/s / -10m/s2 = 5sh = ut + 1/2gt2h = (50m s-1)(5s) + 1/2 (-10m s-2)(5s)2h = 250m + (-5 m s-2)(25s2)h = 250m - 125m = 125m
v = 0 m/s
g = -10m/s2
We know that, v = u + gt
t = (v - u) / g = (0 m/s - 50 m/s) / -10m/s2= -50m/s / -10m/s2 = 5sh = ut + 1/2gt2h = (50m s-1)(5s) + 1/2 (-10m s-2)(5s)2h = 250m + (-5 m s-2)(25s2)h = 250m - 125m = 125m
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