Question

A particle is thrown up with a velocity u at an angle a from the horizontal.Another particle is thrown with the same velocity at an angle a from the vertical,the ratio of times of flight of the two particles will be

Answer 1

☆ Physics
Time of flight for horizontal projectle
Th = root x 2h/g

Time of flight for angular projectle
Ta = 2u sina /g

Ratio :
Th ^2 / Ta^2 = g/2 u sin a

root g : root 2 u sin a

Answer 2

Answer:

tan teta:1

Explanation:

A body is projected with velocity=u

angle of projection =teta

angle=90-teta

B=u

time of flight

a,b =2usinteta/g

ta:tb=sin teta:cos teta

= tanteta:1