Question

A particle is thrown upn vertically with a velocity with a velocity of 50m/sec.How would the particle rise and what time would

Answer 1

u=50m/s

g=-10m/s^2

Velocity at the highest point be 0m/s.

v=0m/s

A/Q

2gh=v^2-u^2

2×(-10)×h=0-2500

h=125

Height=125m

A/Q

v=u+gt

0=50+(-10)×t

t=5

Time=5sec

HOPE IT WILL BE HELPFUL