Question

A particle is thrown upwards from ground it experience a constant resistance force which can produce retardation 2 metre per second square the ratio of time of ascent to the time of descent is

Answer 1

Answer:

Let A be the retardation force. Time for ascent be TTime for descent be T`Now, we know that u = 0 So we have two equations:- S = 1/2 (g-a) T² (for ascent) and S = 1/2 (g+a) T`² (for descent)Divide them and we will get –T/T` = sqrt of (g-a) / sqrt of (g+a) T/T` = sqrt of (10-2) / sqrt of (10+2) Therefore, ratio of T and T` is -Sqrt of 2 / sqrt of 3 .

Explanation:

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