A particle is thrown vertically and velocity 20 m/s . Find the distance travelled by the particle in first 3 seconds and displacement of the particle in 3 seconds...
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remain answer are -
=> s = 60 +(-29.7)
=>s = 60-29.7
=> s = 30.3 m
Hence distance travelled by the Particles in 1st 3 second is 30.3m
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=> s = 60 +(-29.7)
=>s = 60-29.7
=> s = 30.3 m
Hence distance travelled by the Particles in 1st 3 second is 30.3m
Please mark it as brainliest:)
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