Question

a particle is thrown vertically up with a velocity of 50m/s.What will it's velocity at highest point of journey? How high would the particle rise? what time it takes to reach the highest point? (Take the value of g=10m/s

Answer 1

we know that velocity at highest point is 0
thus v=0
using equation 3 of motion
v^2 = u^2 + 2as
0 = 50^2 + 2 x -10 x s
-2500 = -20s
s= 125m

​using equation 2 of motion
s=ut + 1/2 at^2
125 = 50t + 1/2 x -10 x t^2
125 = 50t - 5t^2
t^2 - 10t + 25 = 0
t = 5s