Question

A particle is thrown vertically up with initial speed
30 m/s. Taking acceleration due to gravity as
10 m/s2, the total time of flight of the particle is
(1) 8 s
(2) 6 S
(3) 4 s
(4) 2 s

which formula will apply?​

Answer 1

Answer:

6sec

Explanation:

t=2U/g ,u=30m/s, g=10m/s22

2×30/10= 6sec

Answer 2

The correct answer is 6 seconds.

GIVEN

Initial velocity of the particle = 30m/s

Acceleration due to gravity = 10 m/s²

TO FIND

Total time of the flight.

SOLUTION

We can simply solve the above problem as follows -

Total time of the flight = Time taken to reach h height upwards + Time taken to come down

total time of the flight = 2t

Since at the highest point, The final velocity of the particle is zero.

Applying First equation of motion-

v = u + at

$t \: = \frac{u}{a}$

$t \: = \frac{30}{10} = 3sec$

Total time of the flight = 2×3 = 6 seconds

Hence, The correct answer is 6 seconds.

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