A particle is thrown vertically up with initial
velocity of 60 m/s. The distance covered by the
particle in first two seconds of descent will be
(take g = 10 m/s2)
(1) 5 m
(2) 15 m
(3) 20 m
(4) 40 m
Answers
Answered by
0
Answer:
15 m is the answer ok question
Similar questions