Physics, asked by neharajput1234, 9 months ago

A particle is thrown vertically up with initial
velocity of 60 m/s. The distance covered by the
particle in first two seconds of descent will be
(take g = 10 m/s2)
(1) 5 m
(2) 15 m
(3) 20 m
(4) 40 m​

Answers

Answered by rk4963506
0

Answer:

15 m is the answer ok question

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