Question

a particle is thrown vertically up with speed u so that distance covered in last second of flight is 35 if g is equals to 10 metre per second square then initial speed of throw is

Answer 1

s=u+1/2 a(2n-1)

35- 1/2 10(2(1) -1)= u [distance covered in 1st and last seconds are equal]

u= 30 m/s

Answer 2

Answer:

The particle thrown vertically up with speed is 30 m/s.

Explanation:

Given that,

Distance = 35

The distance covered in last second of flight is 35 m.

We need to calculate the speed of the particle

Using equation of motion

$s=u+\dfrac{1}{2}g(2n-1)$

$u=s-\dfrac{1}{2}g(2n-1)$

Where, g = acceleration due to gravity

s = distance

Put the value into the formula

$u=35-\dfrac{1}{2}\times10(2-1)$

Here, n = 1

$u=30\ m/s$

Hence, The particle thrown vertically up with speed is 30 m/s.