Physics, asked by aryanyadav5678, 10 months ago

A particle is thrown vertically upward from ground
at 55 m/s. Distance travelled by the body in 6th
second is (g = 10 m/s2)​

Answers

Answered by adarshrvskio
1

Answer:

Explanation:u=55m/s

t=6seconds

s=?

solution:

              v^2-u^2=2as

0-55^2/-2*10=s

-110/-20=s

5.5=s

s=5.5mts

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