A particle is thrown vertically upward from ground
at 55 m/s. Distance travelled by the body in 6th
second is (g = 10 m/s2)
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Answer:
Explanation:u=55m/s
t=6seconds
s=?
solution:
v^2-u^2=2as
0-55^2/-2*10=s
-110/-20=s
5.5=s
s=5.5mts
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