Question

A particle is thrown vertically upward if its velocity at half of maximum height is 10 metre per second the maximum height attained by it is

Answer 1

time between 10m/s to 0m/s(after reaching max height)
v=u+at
0=10+(-10)t
-10= -10t
10=10t
t=1

s=ut + 1/2at^2
=10×1+1/2(-10)×1^2
10+(-5)
=5m

so we have found another half which would be equal to first half
so total =5+5=10m