Question

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s, then the maximum height attained by it (g = 10 m/s^2

Answer 1

Dear abhingya

let intitial velocity is U and maximum hight is h

so at maximum hight velocity will be zero

0 =U2 -2gh

U2 =2gh ..........1

now given velocity is = 10m/sec at hight h/2

so 102 = U2 -2gh/2

    100 =2gh -gh

   h = 100/10

  h =10 m/sec

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Answer 2

Answer:

answer is 20 m

Explanation: