Question

a particle is thrown vertically upward with 16m/s from ground. the distance traveledby the particle in first second of decending journey is​

Answer 1

Answer:12.8m

Explanation:

Answer 2

Answer:

Explanation:

v=u+at

0=16-10t

t=1.6 s

distance travelled in 0.6 sec

16-5(0.2)

15

distance travelled in 1.6 sec =

16-5(2.2)

16-11

5m

distance travelled in 1 sec descending journey = 5m