Question

A particle is thrown vertically upward with a velocity of 50m/s what will be its velocity at highest point of the journey? How high would the particl rise

Answer 1

Answer:

U= 50m/s

g= -10m/s^2

The velocity at the highest point will be 0 m/s

Thus v=0

Height can be calculated by

2gs=v^2-u^2

-20s= -2500

s= 125m

Time :

v= u+gt

0=50-10t

-50=-10t

t= 5sec

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Answer 2

✬ Height = 125 m ✬

Explanation:

Given:

• Initial Velocity u = 50m/s
• G = – 10m/s² ( Stone is going upward )
• Final Velocity = 0 ( at Maximum height )

To Find:

• How hight would the particle rise?
• S= ?

Solution: Using :-

★ 2gS = v² – u² ★

• Putting all the values in above formula •

$\small\implies{\sf }$ 2 x (–10) x S = 0² – 50²

$\small\implies{\sf }$ –20S = – 2500

$\small\implies{\sf }$ S = –2500/–20

$\small\implies{\sf }$ S = 125 m

Hence,Maximum height of particle will be 125 m.