Question

A particle is thrown vertically upwards with a speed of 50 metre per second the ratio of distance travelled in second to that in last second of its flight

Answer 1

Answer:

Initial velocity −50m/s(opposite to the direction of acceleration)

Final velocity=10m/s (completing the ascent)

Time taken =

acceleration

0−(−50)

=

10

50

=5s

S

th

=Initial acceleration +

2

1

acceleration (2× (time)-1)

S

4th

=−50+

2

1

×10(7)=−15m

S

5th

=−50+

2

1

×10(9)=−5m

S

4th

+S

5th

=−20m(Negative as it is opposite to direction of acceleration)