Question

A particle is thrown vertically upwards with an
initial velocity of 24-5 m/s.
(iii) After how much time does it return to the ground?
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Answer 1

Answer: 5s

Explanation:

The formula for time of flight of a projectile i.e the particle is $t=\frac{2usin(O)}{g}$ where O is the angle of inclination, u is initial velocity and g is acceleration due to gravity.

Here u = 24.5m/s, O = 90deg, g = 9.8m/s^2.

substituting in the formula we get the answer of 5s.

Answer 2

Answer:

The formula for time of flight of a projectile i.e the particle is t= 2usin(O)/9

where O is the angle of inclination, u is initial velocity and g is acceleration due to gravity.

Here u = 24.5m/s, O = 90deg, g = 9.8m/s^2.

substituting in the formula we get the answer of 5s.