Question

A particle is thrown vertically with velocity 20 m/s . Find (a) the distance travelled by the particle in first 3 seconds, (b) displacement of the particle in 3 seconds.

Answer 1

Answer: Hey ur answer is in the attachment given below

Explanation:

Answer 2

The correct answer is 25m and 15m

By problem

Highest point say B

v = u + g × t

0 = 20 - 10t

t = 2 seconds

distance travel in first 2 seconds.

S = s (t =0 to 2sec) + s (2sec. to 3sec.)

s = (ut + 1/2 at^2 ) + (ut + 1/2at^2)

s = 20 × 2 - 1/2 x 10 x 4 + 1/2 x 10 x 1^2

= (40-20) + 5

= 25 m.

and displacement = 20-5

= 15 m.

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