A particle is thrown vertically with velocity 20 m/s . Find (a) the distance travelled by the particle in first 3 seconds, (b) displacement of the particle in 3 seconds.
Answers
Answered by
4
Answer: Hey ur answer is in the attachment given below
Explanation:
Attachments:
Answered by
2
The correct answer is 25m and 15m
By problem
Highest point say B
v = u + g × t
0 = 20 - 10t
t = 2 seconds
distance travel in first 2 seconds.
S = s (t =0 to 2sec) + s (2sec. to 3sec.)
s = (ut + 1/2 at^2 ) + (ut + 1/2at^2)
s = 20 × 2 - 1/2 x 10 x 4 + 1/2 x 10 x 1^2
= (40-20) + 5
= 25 m.
and displacement = 20-5
= 15 m.
#SPJ3
Similar questions