Question

A particle is thrown with a speed u at an angle theta with the horizontal when the particle makes an angle Alpha with the horizontal its speed becomes V whose values is​

Answer 1

Answer:

V=UCOStheta

Explanation:

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Answer 2

ux=ucos(alpha)

uy=usin(alpha)

when angle =beta.

vx=vcos(beta) that must be equal to ux=ucos(alpha)

so

vcos(beta)=ucos(alpha)

v=ucos(alpha)/cos(beta)