Question

A particle is thrown with a velocity of u m/s it passes AandB as at t1=1 t2=3 the value of u

Answer 1

answer will be (B-A)/2

Answer 2

Answer:40m

Explanation:

motion along y axis .

=>v=u +at

0=usin theta -10t

(given :theta=30degree)

=>u/2 = 10t

=>u/20 = t

here this t time to reach max height ..

t can not be 1 or 3 (because positions of time 1 and 3 are h1 and h2 rspt.)

therefore

time =2sec (in the middle of the given times)

u/20 = 2 sec

therefore

u = 40 m