Question

A particle is thrown with an initial speed of 20m/s.It comes back to the ground after?

Answer 1

Answer:

Explanation:

Initial velocity of the particle = u = 20 m/s (Given)

Final velocity of the particle = v = 0 [ at the maximum height , v = 0 ]

Acceleration due to gravity(g), here will be taken as negative, as the direction of motion of object is opposite to "g".

Hence , g = -9.8 m/s²

Using the second equation of motion -

= v² -u² = 2gh

= 0² - 20² = 2 ×-9.8

= - 400 = -19.6h

= h = - 196/-19.6

= 20. 40m

Therefore, the particle will go 20.40 metres high  before it begins to fall.