a particle is thrown with an initial velocity 20m/s. Calculate the distance and displacement covered by the particle in 3 second ?
Answers
Answered by
0
Answer:
S
n
=u
′
+
2
1
g(2n−1)
Sn=35,g=10ms
−2
,n=t=u/g, initial velocity u
′
=0
−35=
2
1
×−10×[
g
2u
−1]
35=10×
10
u
−5
40=u
u=40m/s
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