Physics, asked by sheshankgpt2174, 1 year ago

a particle is thrown with an initial velocity 20m/s. Calculate the distance and displacement covered by the particle in 3 second ?

Answers

Answered by harshchhawal233
0

Answer:

S

n

=u

+

2

1

g(2n−1)

Sn=35,g=10ms

−2

,n=t=u/g, initial velocity u

=0

−35=

2

1

×−10×[

g

2u

−1]

35=10×

10

u

−5

40=u

u=40m/s

Similar questions