a particle is thrown with angle theta after time t angle becomes alpha. find the initial velocity.
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Answer:
V = gtCosα/Sin(θ - α)
Explanation:
a particle is thrown with angle theta after time t angle becomes alpha. find the initial velocity.
Let say initial velocity = V
Angle = θ
Horizontal Speed = VCosθ
Vertical Speed = VSinθ
after time t
Horizontal Speed = VCosθ
& Vertical Speed = VSinθ - gt
Angle = α
=> Tanα = (VSinθ - gt)/VCosθ
=> Sinα/Cosα = (VSinθ - gt)/VCosθ
=> VSinαCosθ = VCosαSinθ - gtCosα
=> V(SinαCosθ - CosαSinθ) = -gtCosα
=> VSin(α - θ) = -gtCosα
=> VSin(θ - α) = gtCosα
=> V = gtCosα/Sin(θ - α)
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