Question

A particle is thrown with any velocity vertically upward the distance travelled by the particle in first second of its decent is a) g b)g/2 c)g/4 d)cannot be calculated

Answer 1

Answer: I think this is the correct ans

Explanation:

Use S = ut + 0.5at^2

S = 0 + 0.5g(1)^2

S = g/2

I hope that it helped you

Answer 2

Answer:

Distance traveled by a particle in 1st second exists g/2. (b) stands the correct option.

Explanation:

Velocity exists essentially as a vector quantity. It exists the rate of change in distance. It exists the rate of change of displacement. The speed of an object moving can never be negative.

During 1st second descent

Use

$S = ut + 0.5at^2$

$S = 0 + 0.5g(1)^2$

$S = g/2$

Distance traveled by a particle in 1st second exists g/2. (b) stands the correct option.

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