Question

A particle is thrown with initial speed u, at an angle θ with the horizontal. Its speed at the point of maximum height is ______.​

Answer 1

Answer:

No acceleration is there in the horizontal direction so the horizontal component will always be the same.

V

h

=uCosθ

If angle of net velocity is β with horizontal so Tanβ=

V

h

V

v

, V

v

=Vsinβ and V

h

=uCosθ

So Tanβ=

uCosθ

VSinβ

=>V=uCosθ.secβ