Question

A particle is thrown with initial speed U at angle theta with horizontal. Find the time after which velocity of projectile becomes perpendicular to its initial velocity​

Answer 1

Answer:

solved

Explanation:

let theta = ∝

vy = usin∝ - gt

vx = ucos∝

tan(90+∝)  = vy/vx = -1/ tan∝ = usin∝ - gt ÷ucos∝

-tan∝ = ucos∝ ÷ usin∝ - gt

usin∝ - gt = -ucos∝  ÷ tan∝ = - ucos∝cot∝

gt = u (sin∝ +cos∝cot∝) = u(sin∝ +cos²∝/sin∝) = ucosec∝

t = ucosec∝/g = ucsc∝/10  sec.

Answer 2

Hope this solution helps:)