A particle is thrown with speed 10m s in vertically upward direction. find the time when it's speed becomes zero
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h=u^2/2g
h=10^2/2×10
h =100/20
h=5
final velocity =0,
initial velocity =10 and
height or distance =5
1st eq. of motion, we have
v= u+at
10= -10t
t= -1 sec
h=10^2/2×10
h =100/20
h=5
final velocity =0,
initial velocity =10 and
height or distance =5
1st eq. of motion, we have
v= u+at
10= -10t
t= -1 sec
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