Question

A particle is thrown with the speed u at an angle α with the horizontal. When the particle makes an angle β with horizontal, its speed is



Pls answer fast its little urgent.

Answer 1

Explanation:

We know that,

Horizontal component of the velocity remains same through out the motion.

let final velocity making an angle β with the horizontal = v

then, it's horizontal velocity = vcosβ

so,

$u \cos α = v \cos β$

$v = \dfrac{u \cos α}{\cos β}$

$v = u \cos α \sec β$