Question

A particle leaves the origin with an initial velocity
ü = 3 m/s and a constant acceleration
35
a
m/s2. Its speed when its
2
X - coordinate of position is maximum is
(1) 3 m/s
(2)
3
m/s
2
(3) 6 m/s
(4) 9 m/s
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Answer 1

Answer:

Question

A particle leaves the origin with an initial velocity ū=3i m/s and a constant acceleration a= (-i-1/2j) m/s^2. Its speed when its x-coordinate of position is maximumFullscreen

A particle leaves the origin with an initial velocity u⃗ =3i^m/s and a constant acceleration a⃗ =(−i^−12j^)m/s2. Its speed when its

x− coordinate of position is maximum is

1 3m/s

2 32m/s

3 6m/s

4 9m/s

NEET/Medical Exams

Physics

Solution

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A particle leaves the origin with an initial velocity ū=3i m/s and a constant acceleration a= (-i-1/2j) m/s^2. Its speed when its x-coordinate of position is maximum isFullscreen

V⃗ =u⃗ +a⃗ t⇒v⃗ =3i^+(−ı^−12ȷ^)v⃗ =(3−α⃗ )ı^−t2ȷ^

x coordinate will be maximum When x component of velocity is 0

S0,3−t=0⇒t=3

δ0,v⃗ at t=3 is v⃗ =−32ms−2(j^)

So speed =32ms−1

Explanation:

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