A particle makes a smooth periodic motion on a path 20 cm long. When it is 6 cm away from the mean position, its velocity is 26 cm / s. So the value of acceleration when it is 3 cm away from the positive end?
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Answer:
2m/s2
10=20sin ωt
∴ωt=(π6)⇒t=π6ω
The desired time will be 2t
or π3ω=π3(2π/T)=T6=126=2m/s2
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