Question

A particle mass m, carrying charge q is moving in circular path in a plane perpendicular to uniform magnetic field of intensity B. If radius of its path is r, kinetic energy of particle is: (A)q^2.r^2/2mB (B)q^2.B^2.r^2/2m (C)q.B.r^2/2m (D)q.r^2/2mB

Answer 1

Answer:

r madhava warrier in Hindi page no 6 Read three letters words and other clear 20 page no 6 Read three letters words and other clear 20 page no 6 Read three letters words and other clear 20 page

Step-by-step explanation:

h page hai akbar suman in Hindi page no 6 Read three letters words and the last few days and I will be a great day and I will be a great day and I

Answer 2

Answer:

m is to n o

kinetic of masss velocity of accerlation

Step-by-step explanation:

mark as branalist