Question

A particle move along a straight line such that it's displacement at any time t is given by s= t3 -6t2 + 3t+4 meters the velocity when the acceleration is zero is​

Answer 1

v=ds/dt

$3{t}^{2} - 12t + 0 \\ a = \frac{dv}{dt} \\ = 6t - 12$

if a=0

then , 0=6t-12

or ,. t=2s

$v = 3(2) ^{2} - 12 \times 2 \\ v = - 12ms { - }^{2}$

Answer 2

r=6t -3t^2

t=10 s=0

a=dv/dt=6t+6

a(3)^2-12m/5^2

s=fvdt=3t^2-t^3+c

5-3t^2-t^2+c

0=36t-(o) ^3+c

c=0

s=3t^2-t^3

s(3)=0

v=0=6t-3t^2

0=3t(2-t)

t=0,2