Question

a particle Move from position 3 i^ +2j^ - 6k^ to 14i^+13j^+9k^ due to force of f =4i^+j^+3k^. if displacement in meter the work done will be

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Answer 1

Answer:

Here, r

1

=3i+2j−6k and r

2

=14i+13j+9k

So, displacement, (r

2

−r

1

)=(14i+13j+9k)(3i+2j−6k)

=11i+11j+15k

Hence, work done

=F.s

=(4i+j+3k).(11i+11j+15k)

=44+11+45=100J