Question

a particle move in a straight line and it's position at time t is given by x³=2t-1 then the velocity is given by
1. 1/x²
2. 2/3x²
3. 2/3x
4. 1/3x​

Answer 1

Answer:

Explanation:Given x  

2

=2+t Now differentiating this equation with respect to time we get ,

2x  

dt

dx

​  

=1

v=  

dt

dx

​  

=  

2x

1

​  

 

Now again differentiating equation A with respect to dx we get v  

dx

dv

​  

.  

dt

dx

​  

=  

2x

1

​  

dx

v  

dt

dv

​  

=−  

2x  

2

 

1

​  

 

dt

dv

​  

=−  

2x  

2

 

1

​  

(  

2x

1

​  

)=−  

4x  

3

 

1

​