Question

a particle move over three quarters of a circle of radius r (1) what is the direction of motion? (2)what is the magnitude of its direction ?

Answer 1

Answer:

?

Step-by-step explanation:

Easy,

Imagine this problem as a clock,

The hour hand and the minute hand are at 12.

Let's imagine that the hour hand remains intact while the minute hand completes 3 quarters and reaches 9.

The angle between the hour hand and minute hand is 90° (for magnitude only).

So by applying Pythagoras theorem,

Displacement= √(r^2 + r^2))

Which comes out to be r√2.

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