Question

A particle move with a velocity 6i-4j+3k under the influence of a constant force f=20i+15j-5k.the instantaneous power applied to the particle is

Answer 1

Explanation:

Power=Fdv

20icap+15jcap-5kcap.d(6icap-4jcap+3kcap)

=20*6+(15*-4)+(-5*3)

=120-60-15

=45

Answer 2

The instantaneous power applied to the particle is 45 watts.

Explanation:

Given that,

Velocity of the particle, $v=(6i-4j+3k)\ m/s$

Force acting on the particle, $F=(20i+15j-5k)\ N$

The instantaneous power applied to the particle is given by :

$P=F{\cdot}v$

$P=(20i+15j-5k){\cdot}(6i-4j+3k)$

On solving we get :

$P=120-60-15$

P = 45 watts

So, the instantaneous power applied to the particle is 45 watts. Hence, this is the required solution.

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