Question

A particle move with velocity v=1 for time t=1 and V=3
for time t=2 along a straight line. The magnitude of
its average acceleration is​

Answer 1

Answer:

Avg acceleration =change in velocity/time=2/1=2ms-2

Answer 2

Answer:

v = 1m/s

t = 1s

V = 3m/s

T = 2m/s

Avg. acceleration = (v + V)

(t + T)

= 1 + 3

1 + 2

= 4

3

= 4 m/s²

3

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