Physics, asked by rashmipriyem3, 1 year ago

A particle move with velocity v1 for time t1 and v2 for time t2 along a straight line . The magnitude of its average acceleration is .....

Answers

Answered by ajayreddy7474pbt5ya
3

 \frac{t1.t2(v1 + v2)}{v1 + v2}
I think this may be the answer.

rashmipriyem3: Explanation ?
Answered by alinakincsem
1

Please find the answer below:

Keeping in view that, A particle move with velocity v1 for time t1 and v2 for time t2 along a straight line.

The magnitude of its average acceleration is ( v2 - v1 ) / ( t2 - t1)

This calculated with the formula of acceleration i.e:

Acceleration = ( final velocity - initial velocity )/ (change in time)


ashokkanal03: But answer is v2-v1/t1+t2 How?
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