A particle move with velocity v1 for time t1 and v2 for time t2 along a straight line . The magnitude of its average acceleration is .....
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I think this may be the answer.
rashmipriyem3:
Explanation ?
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Please find the answer below:
Keeping in view that, A particle move with velocity v1 for time t1 and v2 for time t2 along a straight line.
The magnitude of its average acceleration is ( v2 - v1 ) / ( t2 - t1)
This calculated with the formula of acceleration i.e:
Acceleration = ( final velocity - initial velocity )/ (change in time)
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