Question

A particle moved along x axis for x=0 to x=5m under the influence of the force.f=(7-2x+3x^2)dx.Find the work done in the process.​

Answer 1

Answer:

F = (7 - 2x + 3x²) N

F = (7 - 2x + 3x²) Nx = 0 to 5m

F = (7 - 2x + 3x²) Nx = 0 to 5mWork done = \int\limits^5_0 {F} \, dx = \int\limits^5_0 {(7-2x+3 x^{2} )} \, dx

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