Question

A particle moves 10m in 4th sec and
15m in 6th sec of its motion. What will
be the initial velocity if motion of the
particle is uniformly accelerated: *​

Answer 1

Answer:

Given : S4 = 10m ; S6 = 15m

Sn = u + a(n - 1/2)

⇒ u + a(4-1/2) = 10 ⇒ u+ 7a/2 = 10m  ------ i

case ii = u + a(6 - 1/2) = 15 = u + 11a/2 = 15m ------ ii

On solving i and ii

we get  a = 2.5 m/s² and u = 1.25m/s

Of S₇ = 1.25 + 2.5(7 - 0.5)

On simplification We Get S₇ = 17.5 m

Explanation:

hope it helps n plz mark as brainiest