Question

a particle moves 3M north and then 4m east and finally 6M South calculate the distance travelled and displacement​

Answer 1

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Answer 2

Answer:

Explanation:

The particle travels from a to b to c to finally, d. The displacement will be the distance from initial to final points or, from a to d.

Thus, in triangle aa'd by using pythagoras theorem

ad^2 = 3^2 +4^2 = 25

thus, displacement, ad = 5 m

the total distance travelled will be equal to ab + bc + cd = 3m + 4m +

6m

or

distance = 13 m