Question

a particle moves 3m north then 4m east and finally 6m south. calculate the displacement

Answer 1

The particle travels from a to b to c to finally, d. The displacement will be the distance from initial to final points or, from a d.

The particle travels from a to b to c to finally, d. The displacement will be the distance from initial to final points or, from a to d.Thus, in triangle aa'd by using pythagoras theoremad^2 = 3^2 +4^2 = 25

The particle travels from a to b to c to finally, d. The displacement will be the distance from initial to final points or, from a to d.Thus, in triangle aa'd by using pythagoras theoremad^2 = 3^2 +4^2 = 25thus, displacement, ad = 5 m

Answer 2

Answer:

5 m

Explanation:

Let north, south east be represented by N, S, E.

According to question:

⇒ 3m in North = 3N,  then

⇒ 4m in East(right) = 3N + 4E , then

⇒ 6m in South = 3N + 4E + 6S

Total displacement = 3N + 4E + 6S

But as we know, north is opposite to south, N = - S.

∴ displacement = 3(-S) + 4E + 6S = 4E + 3S  

As south and east are at right angle to each other, we can't them directly.

Using Pythagoras theorem,

Displacement = √3² + 4² = 5

Displacement is 5 m