Question

A particle moves 3M North then 4th M east and finally 6M South calculate the displacement​

Answer 1

Explanation:

let us draw the figure for the path trasversed :- see the fig

let displacement= ā

a²=(os')² + (ss')²

os'=NE=4m

and ss'=SE-ES'=>SE-ON=(6-4)m=2m

:.a=√(4²+2²) =√20m

Answer 2

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$Heya$

Distance - 13m

Displacement - 5m

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