A particle moves a distance of 2000 m .of the first half distance is covered at 40 km/h and the second half distance with speed v and the average speed is 48 km/h then the value of v ?
Answers
Answered by
5
Time to cover first half = 1/40hrs
Time to cover the second half = 1/vhrs
Average speed = total distance/total time=2/1/40+1/v=48
From the above equation v = 60 km/hr
Time to cover the second half = 1/vhrs
Average speed = total distance/total time=2/1/40+1/v=48
From the above equation v = 60 km/hr
Similar questions