A particle moves a distance of 3km towards east and then 4km towards north.
(a)Find the total distance traveled by the particle?
(b)Calculate the net displacement of the particle?
plz help fast
Answers
Answered by
1
Answer:
(i) Total distance travelled =3+4+9=16 km
(ii) The body travels a total distance of 12 km in east direction i.e. towards x-axis.
And it travels a distance of 4 km in North direction, i.e. towards y-axis.
Hence, resultant displacement is
=122+42=144+16=160=12.6km
hope it helps you a lot.
Answered by
0
Answer:
Hope it will be helpful to you
Explanation:
1. Total distance travelled =3+4+9=16 km
2. is given on attachment
Attachments:
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