Science, asked by ayesha200781, 1 month ago

A particle moves a distance of 3km towards east and then 4km towards north.

(a)Find the total distance traveled by the particle?

(b)Calculate the net displacement of the particle?

plz help fast ​

Answers

Answered by sonydigital49
1

Answer:

(i) Total distance travelled =3+4+9=16 km

(ii) The body travels a total distance of 12 km in east direction i.e. towards x-axis. 

And it travels a distance of 4 km in North direction, i.e. towards y-axis. 

Hence, resultant displacement is 

=122+42=144+16=160=12.6km

hope it helps you a lot.

Answered by sk7838596034
0

Answer:

Hope it will be helpful to you

Explanation:

1. Total distance travelled =3+4+9=16 km

2. is given on attachment

Attachments:
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