Question

A particle moves a distance x in time t according
to equation x = (t + 5)^-1. The acceleration of particle
is proportional to [AIPMT (Prelims)-2010)
(1) (Velocity)^3/2
(2) (Distance)^2
(3) (Distance)^-2
(4) (Velocity)^2/3​

Answer 1

Answer:

distance x=(t+5)^−1

velocity v=dx\dt=−(t+5)^−2

acceleration a=dv\dt=2(t+5)^−3

Therefore v^3/2=−(t+5)^−3

Therefore a=−2v^3/2

a. v^3/2

Hence a is the correct answer.

Answer 2

Answer:

Explanation:

Here's the solution to your question.

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